What happens when you compile and run this code?
class Parent { static void greet() { System.out.println("Parent"); } }
class Child extends Parent { static void greet() { System.out.println("Child"); } }
Parent p = new Child();
p.greet();

Question

Accepted Answer

Static methods are resolved at compile time based on the reference type, not the runtime object type — this is called method hiding, not overriding. Since p is declared as Parent, Parent.greet() is called, printing "Parent".

What happens when you compile and run this code? class Parent { static void greet() { System.out.println("Parent"); } } class Child extends Parent { static void greet() { System.out.println("Child"); } } Parent p = new Child(); p.greet();

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